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  • Help Me With HomeWork Thread!

    So I know a whole bunch of us are still in school on here so I thought this would be an excellent idea for a thread.

    Tonight physics is kicking my ass.

    Here are some of the questions.

    A spring loaded projectile launcher is used to launch a ball of mass 50 grams into the air at a given angle. In this particular instance, the launcher is set at an angle of 30o with the ground when the ball is placed in and the spring is compressed a distance of 12 centimeters from rest. The spring has a constant of 3.9 N/cm. Assume the initial height of the ball to be zero. Find the following (Neglect Air Resistance for parts a-c)

    a. The Maximum Height reached by the ball
    b. The Potential Energy of the Ball at its Maximum Height.
    c. The Kinetic Energy of the Ball at its Maximum Height.

    The Launcher is then reset at 90o with the ground and loaded with the same ball, but is compressed 15 centimeters from rest. When launched the ball reaches a Maximum Height of 7.5 meters above zero. Assume air resistance is NO LONGER NEGLIGIBLE, and that the initial height of the ball is still zero.

    d. Calculate the energy lost due to air resistance.
    - Kielan (Key-lin)

  • #2
    good god.....i'm gonna have nightmares of my physics classes back in highschool lol. i'll dig around my old stuff and read over it if i can find it.
    Pose for the frame

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    • #3
      Ok well just found out I dont have to do that. But I do have to do another one that involves (A=Delta)
      FAT=mAv, I am trying to find the force in that. But I have no idea what to do for m and v because I have 2 cars that have collided (inelastic collision). Ughhhh I **** this.
      - Kielan (Key-lin)

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      • #4
        Physics came easy to me man. I got the highest final grade in my class lol 98%

        -Dan

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        • #5
          Well don't just sit there Dan, help a brother out!
          - Kielan (Key-lin)

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          • #6
            If I remember back three years ago, you have to find out how much car 1 weights x the traveling speed as well as car 2. Then that is the force of traveling of the two, subtract that from each other and that is how much force is left. Is that what your asking?

            Wheres the dont know but maybe smiley face lol.

            -Dan

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            • #7
              Here is the exact question for those wondering.

              2. Two bumper cars at a local carnival collide head on in what is to be considered a completely Elastic Collision.
              a. Using Newton's 3rd Law of Motion and The Impulse-Momentum Theorem, derive the Law of Conservation of Momentum in terms of the mass of Car A, mA, the velocity of Car A, vA, the mass of Car B, mB, and the velocity of Car B, vB. (This is to be considered a Mathematical Proof).
              The mass of Car A plus its driver is 182 kg and a speed of 5.5 m/s, while the combined mass of Car B and its driver is 112 kg with a speed of 3.3 m/s. After the collision, Car B moves back in the opposite direction of its original motion with a speed of 7.0 m/s. Find the following:

              The final velocity of Car A (both magnitude and direction) Answered this already.

              The average force of impact if the collision lasted for 5.0 ms.
              - Kielan (Key-lin)

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              • #8
                I know how to do it, but I cant explain it lol I know car A is traveling faster/weights more tho

                -Dan

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                • #9
                  Its all good I think I got it.

                  Oh and state the obvious much?
                  - Kielan (Key-lin)

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                  • #10
                    Originally posted by prodigee View Post
                    Its all good I think I got it.

                    Oh and state the obvious much?
                    I didnt even read that it was given Just read the part of car B moved back 7m/s afterwards lol

                    -Dan

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                    • #11
                      Originally posted by wheelfetish View Post
                      I didnt even read that it was given Just read the part of car B moved back 7m/s afterwards lol
                      :facepalm:
                      - Kielan (Key-lin)

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